A → [( (B ∧ C ) ∨ D) → A] TRUE

A
inference logicA → (((B ∧ C) ∨ D) → A)
0

Truth check table

CaseABCDA → (((B ∧ C) ∨ D) → A)
1TTTTT
2TTTFT
3TTFTT
4TTFFT
5TFTTT
6TFTFT
7TFFTT
8TFFFT
9FTTTT
10FTTFT
11FTFTT
12FTFFT
13FFTTT
14FFTFT
15FFFTT
16FFFFT
Public: Yes; Show truth table: Yes;