A ∧ (B ∧ C ) ∴ (A ∧ B) ∧ C TRUE

A ∧ (B ∧ C)
inference logic(A ∧ B) ∧ C
0

Truth check table

CaseABCA ∧ (B ∧ C)(A ∧ B) ∧ C
1TTTTT
2TTFFF
3TFTFF
4TFFFF
5FTTFF
6FTFFF
7FFTFF
8FFFFF
Public: Yes; Show truth table: Yes;