check (A → C) ↓ B ∧ C → B TRUE

(A → C) ↓ B
inference logicC → B
0

Truth check table

CaseACB(A → C) ↓ BC → B
1TTTFT
2TTFFF
3TFTFT
4TFFTT
5FTTFT
6FTFFF
7FFTFT
8FFFFT
Public: Yes; Show truth table: Yes;