Equival (A → B) ↔ ( ~ A ∨ B) TRUE

A → B
( ~ A) ∨ B
inference logic(A → B) ↔ ( ~ A ∨ B)
0

Truth check table

CaseABA → B( ~ A) ∨ B(A → B) ↔ ( ~ A ∨ B)
1TTTTT
2TFFFT
3FTTTT
4FFTTT
Public: Yes; Show truth table: Yes;