check2 TRUE

p ∧ (q ∨ r)
inference logic(p ∧ q) ∨ (p ∧ r)
0

Truth check table

Casepqrp ∧ (q ∨ r)(p ∧ q) ∨ (p ∧ r)
1TTTTT
2TTFTT
3TFTTT
4TFFFF
5FTTFF
6FTFFF
7FFTFF
8FFFFF
Public: Yes; Show truth table: Yes;