p ; p → q ; q → r ∴ p ∧ (q ∧ r) TRUE

p
p → q
q → r
inference logicp ∧ (q ∧ r)
0

Truth check table

Casepqrp → qq → rp ∧ (q ∧ r)
1TTTTTT
2TTFTFF
3TFTFTF
4TFFFTF
5FTTTTF
6FTFTFF
7FFTTTF
8FFFTTF
Public: Yes; Show truth table: Yes;